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exponential int

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bananna:
hello :)

can someone pls help me with this q
I'm used to just dealing with linear exponential functions
so have trouble with this

thank you!! :)

jakesilove:

--- Quote from: bananna on March 01, 2017, 03:39:12 pm ---hello :)

can someone pls help me with this q
I'm used to just dealing with linear exponential functions
so have trouble with this

thank you!! :)

--- End quote ---

Hey!



This is because



So, it's clear that



ie. If we differentiate something, then integrate it again, it because the original function. However, because we have completed an indefinite integral, we have to remember to plus C. Does that make sense?

bananna:

--- Quote from: jakesilove on March 01, 2017, 03:51:20 pm ---Hey!



This is because



So, it's clear that



ie. If we differentiate something, then integrate it again, it because the original function. However, because we have completed an indefinite integral, we have to remember to plus C. Does that make sense?

--- End quote ---


yes it makes sense

thank you!! :)

bananna:

--- Quote from: jakesilove on March 01, 2017, 03:51:20 pm ---Hey!



This is because



So, it's clear that



ie. If we differentiate something, then integrate it again, it because the original function. However, because we have completed an indefinite integral, we have to remember to plus C. Does that make sense?

--- End quote ---


just clarifying--

2xe^x^2+3
 is divided by the differential of x^2 = (2x)

and that cancels with 2x on the top to give the integrated form, which is =e^x^2+3 + C ?

thnx

jamonwindeyer:


--- Quote from: bananna on March 02, 2017, 11:41:10 am ---
just clarifying--

2xe^x^2+3
 is divided by the differential of x^2 = (2x)

and that cancels with 2x on the top to give the integrated form, which is =e^x^2+3 + C ?

thnx

--- End quote ---

Pretty much! It is kind of like integrating with the chain rule; you have to be really careful when you do it, and they'll usually lead you into it like they have here!

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