PLZZ help Asap Arg(z-1+i)=alpha

[nick7862]

how do i turn Arg(z-1+i)=alpha into Cartesian form, i need this asap plzz help

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how do i turn Arg(z-1+i)=alpha into Cartesian form, i need this asap plzz help

You know arg(z-(1-i))= alpha and from that form you know the open circle is at ( 1,-1) it's a linear line and the gradient of it is tan(alpha). So the line is tan(alpha)x+c the sub 1,-1 to get your line in terms of alpha it really depends what alpha is