Trig Application Question

[Aqualim]

Hey,
I'm having a bit of trouble with the question attached below.

By the way the equation for the sine graph is; 2sin(3x)+2

I'm thinking that for question (f) that i would just type the equation into the CAS calc under the derivitive function and get an answer, i think i was 6cos(3x) or something.

OR

Do I draw the graph of the original function, then mark a tangent point at pi/3, and write down the equation of that point

[cobby]

Hey,
I'm having a bit of trouble with the question attached below.

By the way the equation for the sine graph is; 2sin(3x)+2

I'm thinking that for question (f) that i would just type the equation into the CAS calc under the derivitive function and get an answer, i think i was 6cos(3x) or something.

OR

Do I draw the graph of the original function, then mark a tangent point at pi/3, and write down the equation of that point

It says find the gradient at that point, so I assume you wouldn't have to show it on the graph itself. Just plug it into the calculator and state the answer.

[Aqualim]

alright cheers, also for question (g)
would it just be;

[Flaming_Arrow]

alright cheers, also for question (g)
would it just be;

since the gradient is negative

180 - tan^-1(6)

[Aqualim]

alright cheers, also for question (g)
would it just be;

since the gradient is negative

180 - tan^-1(6)

wouldn't it also be included in the 4th quadrant, instead of just the 2nd?

[Flaming_Arrow]

alright cheers, also for question (g)
would it just be;

since the gradient is negative

180 - tan^-1(6)

wouldn't it also be included in the 4th quadrant, instead of just the 2nd?

na, in this case you want the angle that the line makes with the POSITIVE x axis