Complex Numbers

[TrueTears]

Do it on ur TI-89 if you forget in exam, factor(z^3+64,x)

[/0]

How do you factorise things like
theres 2 formulas but i forgot them lol

, then complete the square and DOPS

[d0minicz]

thanks
whats the other one ?

[TrueTears]

a^3-b^3 = (a-b)(a^2+ab+b^2)

[d0minicz]

Need a run through on how to answer these !

Shade the region of the Argand plane specified by where
a) and

b) Hence find the exact area of the shaded region

thanks....

[TrueTears]

Let





For the Argument I like to think of it graphically with transformations rather than algebraically (for once I actually like graphic method lol)

is just translated 2 units to the left on the x axis.

The angle it bounds is from the horizontal x axis to the angle

Remember for open dot at the 'origin' which is at

for , shade in the region that belongs to both sets.

[d0minicz]

ahh cheers

i dont get where to shade it in (the part)

also still confused about the area lols

=] =]

[TrueTears]

It's just the area where the areas of S and T intersect.

You know only Venn Diagram A n B, is the 2 intersections of the circles.

Same principle here.

[Wei]

if i type cSolve (3z-conj(z)=12-4i,z) into my Ti-89 Titanium, i get 6-2i. But if i solve it manually, i get 6-i. Does anyone know how to overcome this and why this occurs?

[Mao]

Need a run through on how to answer these !

Shade the region of the Argand plane specified by where
a) and

b) Hence find the exact area of the shaded region

thanks....

- donut with r = 1 and R = 2 centered at (-2,0)
- 0 to 60 degree section centered at (-2,0)

Their intersection gives the 0 to 60 degree portion of the donut. This is one sixth of a full donut.

the area of the donut is , hence one-sixth of this will give unit squared.