Single displacement

[almostdonewithschooling]

Hey guys,

Just wondering,

Is this right?

Aluminium metal reacts with aqueous copper (II) nitrate

Would be:

Al(s) + Cu(NO3)2(aq) ---> Al(NO3)2 + Cu(s) when you balance it?


Thankss

[Yertle the Turtle]

Hey guys,

Just wondering,

Is this right?

Aluminium metal reacts with aqueous copper (II) nitrate

Would be:

Al(s) + Cu(NO3)2(aq) ---> Al(NO3)2 + Cu(s) when you balance it?


Thankss

Aluminum makes a 3+ ion, so it will be Al(NO3)3 instead. Therefore the balancing will be different:
2Al(s) + 3Cu(No3)2(aq) → 2Al(No3)3(aq) + 3Cu(s)

[almostdonewithschooling]

Haha oopsy. Could you also tell me why the right side state is in (s) and (aq)?

Doesn't make sense because the Ba is a metal and SO is a non-metal. (S) is meant to be metal and metallic right?

[Lear]

Solubility rules sulfates are insoluble with barium

[Yertle the Turtle]

Haha oopsy. Could you also tell me why the right side state is in (s) and (aq)?

Doesn't make sense because the Ba is a metal and SO is a non-metal. (S) is meant to be metal and metallic right?

(Image removed from quote.)

Don't think of it as the (S) being by itself, think of it as being a sulfate ion, and therefore when it is part of an ionic compound with a metal it can be solid or aqueous, and here is where you use your solubility laws to find out if it is soluble or insoluble. Just a side point, this formula is incorrect, as it hasn't been balanced. I don't know if that occurs later in the video or not, but just remember this anyway. Always balance