Methods question HELP!

[mathsfailure]

Please help!

A quadratic rule for a particular parabola is of the form y = ax2 + bx. The parabola passes through the point with coordinates (−1,4) and one of its x-axis intercepts is 6. Find the values of a and b.

[GMT. -_-]

Just create two equations from the given info and solve simultaneously and you'll get your 2 values.
1 - 0=36a+6b
2 - 4=a-b

[mathsfailure]

Thanks!

[mathsfailure]

Got one more

A quadratic rule for a particular parabola is of the form y = a(x−b)2 + c. The parabola has vertex (1,6) and passes through the point with coordinates (2,4). Find the values of a, b and c.

[PolySquared]

You need to create two similtaneous equations by substituting in you given values in place of the x and y variables:




You can enter this on your CAS by pressing menu - 3,7,1 - or just solve it by hand. I hope this helps 

[PolySquared]

Got one more

A quadratic rule for a particular parabola is of the form y = a(x−b)2 + c. The parabola has vertex (1,6) and passes through the point with coordinates (2,4). Find the values of a, b and c.

Start by creating an equation using the turning point information provided:



Then substitute the other coordinates of (2,4) into the place of x and y



Now just solve for a




Now just place the value of a back into the original equation



Hope this helps 

[mathsfailure]

Thank you so much for your help!