Login

Welcome, Guest. Please login or register.

November 01, 2025, 09:47:30 am

Author Topic: Motion Question  (Read 1001 times)  Share 

0 Members and 1 Guest are viewing this topic.

chaput

  • Trailblazer
  • *
  • Posts: 29
  • Respect: 0
  • School: Mount Waverley Secondary College
  • School Grad Year: 2020
Motion Question
« on: March 12, 2018, 10:40:43 am »
0
Hi there, could someone please help me out with the questions below:

A skier, starting from rest, accelerates at a constant rate down a flat (i.e. no bumps) slope in
a straight line.

a. It takes the skier 6 s to travel 108 m. What is the skier’s average acceleration in ms-2?

b. How fast is the skier going at this time (i.e. 6 seconds after starting)?


THANK YOUUUU HELP IS ALWAYS APPRECIATED:)

Yertle the Turtle

  • Forum Leader
  • ****
  • Posts: 987
  • This page is blank
  • Respect: +478
Re: Motion Question
« Reply #1 on: March 12, 2018, 11:09:21 am »
0
Hi there, could someone please help me out with the questions below:

A skier, starting from rest, accelerates at a constant rate down a flat (i.e. no bumps) slope in
a straight line.

a. It takes the skier 6 s to travel 108 m. What is the skier’s average acceleration in ms-2?

b. How fast is the skier going at this time (i.e. 6 seconds after starting)?


THANK YOUUUU HELP IS ALWAYS APPRECIATED:)
You would simply use the motion equations since you know time (6s), initial velocity (0m/s) and displacement (108m):
a) s=ut+1/2at^2
=>a=(2(s-ut))/t^2
=>a=(2*108)/36=6m/s^2

b) s=1/2(v+u)t
=>v=(2s/t)-u
=>v=36m/s
2017-2018: VCE
Methods | Specialist | Physics | Chemistry | English | Texts and Traditions

2019: B. Eng (Hons) | Monash
2019-?: Certificate III  in Bricklaying and Blocklaying

Have counted to 80