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November 08, 2025, 05:14:14 am

Author Topic: Displacement and Velocity  (Read 548 times)  Share 

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mandy

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Displacement and Velocity
« on: October 13, 2009, 06:18:09 pm »
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The position of a body between the times t=0 and t=10 is given by the equation x = t2-6t+5, where t is the time in seconds and x is the position in metres.
a. Sketch the position-time graph for 0<t<10.
Done
b. Calculate the average velocity between 2s and 4s.
0m/s
c. Calculate the average velocity between 1s and 5s.
0m/s
d. Calculate the average speed between 2s and 4s.
I tried finding the turning pt. of the graph and using that to find the distance travelled, but that was wrong.
How do I do this question?
2009:
Biology [34]   Vietnamese [36]
2010:
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2010 ATAR: 97.20
2011: Bachelor of Biomedicine @ UniMelb

arthurk

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Re: Displacement and Velocity
« Reply #1 on: October 13, 2009, 06:56:52 pm »
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The answers are in ur bio exams
if u get what im saying

TrueTears

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Re: Displacement and Velocity
« Reply #2 on: October 13, 2009, 07:01:26 pm »
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Avg speed is defined as
PhD @ MIT (Economics).

Interested in asset pricing, econometrics, and social choice theory.

mandy

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Re: Displacement and Velocity
« Reply #3 on: October 13, 2009, 08:14:45 pm »
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Okay, so here was my way of doing this..
I tried to find the turning point of x=t2-6t+5, and I got the turning point of (3,-4).
I then added this to the distance of 5. ---> 5+4+4=13
Then, I divided the 13 by 2, which is the change in time, i hope.
I got an answer of 6.5m/s, while the correct answer is meant to be 1m/s :S
Help please ?
2009:
Biology [34]   Vietnamese [36]
2010:
English [48]   Chemistry [37]   Further [38]   Methods [39]   Specialist [29]
2010 ATAR: 97.20
2011: Bachelor of Biomedicine @ UniMelb

mandy

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Re: Displacement and Velocity
« Reply #4 on: October 13, 2009, 08:29:46 pm »
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Okay, thank you, I got it :)
2009:
Biology [34]   Vietnamese [36]
2010:
English [48]   Chemistry [37]   Further [38]   Methods [39]   Specialist [29]
2010 ATAR: 97.20
2011: Bachelor of Biomedicine @ UniMelb