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October 21, 2025, 10:31:23 pm
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Author Topic: Chemistry  (Read 949 times)  Share 

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Katie-E

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Chemistry
« on: August 01, 2018, 09:41:27 pm »
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Hey, I was wondering whether anyone could please help me with these calculations. the second is attached. Cheers  ;)

6. 14 g of coal undergoes complete combustion in 58 g of oxygen gas.
What volume of gas (measured at 25 oC and 100 kPa) is present when the reaction is
complete?
(A) 16 L
(B) 29 L
(C) 45 L
(D) 74 L
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dermite

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Re: Chemistry
« Reply #1 on: August 12, 2018, 06:58:59 pm »
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assume coal is 100% carbon (solid)
thus
use moles = mass/molar mass:
14/12.01 = 1.165695254
multiply this by 24.79 (value for STP)

1.165695254 x 24.79 = 28.897...
                                   ~ 29L
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