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November 01, 2025, 10:31:13 am
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Author Topic: VCAA 2007 Exam 2, Module 5 Q1  (Read 906 times)  Share 

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Zaljc

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VCAA 2007 Exam 2, Module 5 Q1
« on: October 08, 2018, 08:53:34 pm »
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Hey guys,

I learnt that connected graphs are when all the vertices connect, EVEN when the lines cross. I checked the textbook and online, and it said the same thing.

So then why is the number minimum edges for this question 4? If you do an ‘X’ cross and add another one to three, the minimum is 3, not 4.

Someone please correct me I’m so confused
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2018- Chemistry, English, Methods, Physics & Business Managment

lemonlemonlemon

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Re: VCAA 2007 Exam 2, Module 5 Q1
« Reply #1 on: October 10, 2018, 09:56:04 am »
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 Connected networks means that from one vertices you can always travel to all vertices wherever you're at (edges). Another way to visualise this is because the electric cable is singular and cannot be splitted as there can only be one source.
« Last Edit: October 10, 2018, 11:09:00 am by lemonlemonlemon »
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Zaljc

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Re: VCAA 2007 Exam 2, Module 5 Q1
« Reply #2 on: October 10, 2018, 04:24:51 pm »
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Quote from: lemonlemonlemon on October 10, 2018, 09:56:04 am
Connected networks means that from one vertices you can always travel to all vertices wherever you're at (edges). Another way to visualise this is because the electric cable is singular and cannot be splitted as there can only be one source.

Thank you! Time to re-write my notes!
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2018- Chemistry, English, Methods, Physics & Business Managment
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