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Author Topic: Chloride ion concentration in water help  (Read 1194 times)  Share 

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CA15

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Chloride ion concentration in water help
« on: October 27, 2018, 09:19:17 pm »
+1
https://imgur.com/a/BcqX7ir

I need help with calculating the concentration of chloride ions in a sample of water using the following steps as seen in the photo linked.

Average volume of silver nitrate: 68.3ml

Thanks
« Last Edit: October 27, 2018, 09:22:14 pm by CA15 »

AngelWings

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Re: Chloride ion concentration in water help
« Reply #1 on: October 27, 2018, 10:04:54 pm »
+3
Before we dive in, why don't you let us know how much you could do of these questions, what calculations you think you need to use and why you think you need to use these calculations? This'll help you far more in the future than us simply stating outright that X is the answer. We're happy to help you out, but it'd probably be best to know exactly where you're stuck here or find any potential misconceptions. You probably know much more than you think you do too. :) 

P.S. I wasn't intending on being rude at all. I just think you should tell us what you think you'd do to approach the question.  :D
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CA15

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Re: Chloride ion concentration in water help
« Reply #2 on: October 27, 2018, 11:09:56 pm »
0
Before we dive in, why don't you let us know how much you could do of these questions, what calculations you think you need to use and why you think you need to use these calculations? This'll help you far more in the future than us simply stating outright that X is the answer. We're happy to help you out, but it'd probably be best to know exactly where you're stuck here or find any potential misconceptions. You probably know much more than you think you do too. :) 

P.S. I wasn't intending on being rude at all. I just think you should tell us what you think you'd do to approach the question.  :D

Specifically with question 2, I don’t understand how to calculate the number of moles of silver nitrate needed to react with the chloride ions, and I don’t understand how the relationship moles of solute = molarity x volume can be used to find that.

CA15

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Re: Chloride ion concentration in water help
« Reply #3 on: October 28, 2018, 07:21:44 am »
0
B

Bri MT

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Re: Chloride ion concentration in water help
« Reply #4 on: October 28, 2018, 11:06:44 am »
+2
B


Please don't bump your post when it's been less than 24 hours since the your earlier post. We're happy to help people through their VCE but helpful people like AngelWings (and even mods) are unpaid volunteers. We need sleep too, and bumping posts (especially within short timeframes) clutters the forums. I don't doubt that you didn't intend anything bad & that you're probably stressed and just wanting help, but please keep this in mind for the future.


If no-one has helped out by more by then, I'll take a look at your question after I've done a practice for my exam tomorrow :)

CA15

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Re: Chloride ion concentration in water help
« Reply #5 on: October 28, 2018, 03:02:44 pm »
0

Please don't bump your post when it's been less than 24 hours since the your earlier post. We're happy to help people through their VCE but helpful people like AngelWings (and even mods) are unpaid volunteers. We need sleep too, and bumping posts (especially within short timeframes) clutters the forums. I don't doubt that you didn't intend anything bad & that you're probably stressed and just wanting help, but please keep this in mind for the future.


If no-one has helped out by more by then, I'll take a look at your question after I've done a practice for my exam tomorrow :)

Thanks so much

Bri MT

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Re: Chloride ion concentration in water help
« Reply #6 on: October 28, 2018, 07:28:15 pm »
+2
The average volume of AgNO3 is  68.3 mL
Let's first change this to 0.0683 L to make sure we use the right units in calculations

vol (AgNO) * conc(AgNO3) = n(AgNO3) = n(Cl-) = vol(Cl-) * conc(Cl-)

it seems like you're provided the value for n(Cl-), in which case you can find conc(AgNO3) using this equation:
n(Cl-)/0.0683 = conc(AgNO3)   note that we can only do this because the n(Cl-) = n(AgNO3).   

The equation n(AgNO3)/vol(AgNO3) = conc(AgNO3) will always be true as long as you use the right units

CA15

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Re: Chloride ion concentration in water help
« Reply #7 on: October 28, 2018, 07:52:46 pm »
0
The average volume of AgNO3 is  68.3 mL
Let's first change this to 0.0683 L to make sure we use the right units in calculations

vol (AgNO) * conc(AgNO3) = n(AgNO3) = n(Cl-) = vol(Cl-) * conc(Cl-)

it seems like you're provided the value for n(Cl-), in which case you can find conc(AgNO3) using this equation:
n(Cl-)/0.0683 = conc(AgNO3)   note that we can only do this because the n(Cl-) = n(AgNO3).   

The equation n(AgNO3)/vol(AgNO3) = conc(AgNO3) will always be true as long as you use the right units

Thanks so much for the response, it finally makes a lot of sense. I can now do the calcultikns for my other water samples.