URGENT HELP NEEDED

[kdgamz]

i have this mind block and i gotta fix it asap

for exam 1 08 ...question 3..is this the proper way to start?

k1(a) + k2(b) + k3(c) = 0 where k1, k2, and k3 is not equal to zero

i expand and group all i , j and k components, then equate all of them to zero and solve for m and n, then find the ratio of m:n

THANKS heaps

[GerrySly]

What exam 1 from '08?

[kdgamz]

What exam 1 from '08?

spesh man

[arthurk]

looks like linear dependence in which case yeah should be fine

[kdgamz]

sorry guys.....VCAA exam 1, 08..this is a specific case and i dont think what i did can be right!!

help??

[/0]

If you do you will have 3 equations in 5 pronumerals.

You can reduce the number of pronumerals like this:





Then let ,



This is an equivalent definition, but it only works if . If then and must be scalar multiples of each other. Check this isn't the case for each pair of vectors before using the formula. If it is the case that one vector is a multiple of another then all three vectors are linearly dependent from our starting definition.

[kdgamz]

If you do you will have 3 equations in 5 pronumerals.

You can reduce the number of pronumerals like this:





Then let ,



This is an equivalent definition, but it only works if . If then and must be scalar multiples of each other. Check this isn't the case for each pair of vectors before using the formula. If it is the case that one vector is a multiple of another then all three vectors are linearly dependent from our starting definition.

no i get the right answer using my way...i just want to know whether its right...please check vcaa exam 1 08

[Mao]

Your way is correct.

[kdgamz]

Your way is correct.

1.5 hrs to go and now im content
 thanks man