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November 08, 2025, 07:05:44 am

Author Topic: A quick question  (Read 1747 times)  Share 

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TrueTears

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A quick question
« on: October 29, 2009, 06:13:57 pm »
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How do you sketch

So normally for these questions I just apply transformations.

First let



So it's the ray that makes an angle of radians with horizontal then shifted 2 to the left in the real axis and then rotated 90 degrees clockwise. However that's wrong... how does it actually look like?
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mano91

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Re: A quick question
« Reply #1 on: October 29, 2009, 06:22:41 pm »
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does the solution look like the line y= x/sqrt(3)  +2 ?
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TrueTears

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Re: A quick question
« Reply #2 on: October 29, 2009, 06:24:18 pm »
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does the solution look like the line y= x/sqrt(3)  +2 ?
I never use and change into cartesian simply because doesn't work all the time, I've always applied transformations like this and never failed me, I don't know why this one it doesn't work.
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TrueTears

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Re: A quick question
« Reply #3 on: October 29, 2009, 06:25:20 pm »
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Btw I know you can split up the into

But I want a way where you don't have to split it up.
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NE2000

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Re: A quick question
« Reply #4 on: October 29, 2009, 06:46:39 pm »
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Maybe translation ought to be which comes out to be so you shift it up 2 and then you do the rotation.
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TrueTears

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Re: A quick question
« Reply #5 on: October 29, 2009, 07:08:02 pm »
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Thanks, I realised the question actually asked for something different lol.

Another Q is sketching even possible?
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Re: A quick question
« Reply #6 on: October 29, 2009, 07:48:52 pm »
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it's impossible

TrueTears

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Re: A quick question
« Reply #7 on: October 29, 2009, 07:49:42 pm »
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it's impossible
Yeah I asked kamil, says you need taylor series. GG
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Re: A quick question
« Reply #8 on: October 29, 2009, 07:51:21 pm »
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Arg(z) is real though, so it won't be able to cancel out the , leaving the left side complex with an imaginary part and the right side real.

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Re: A quick question
« Reply #9 on: November 17, 2009, 08:17:30 pm »
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How do you sketch

So normally for these questions I just apply transformations.

First let



So it's the ray that makes an angle of radians with horizontal then shifted 2 to the left in the real axis and then rotated 90 degrees clockwise. However that's wrong... how does it actually look like?

arg(iz+2)=2pi/3

let z=x+iy

arg(i(x+iy)+2)=2pi/3

pi/2+arg[x+2+i(y)]=2pi/3

arg[(x+2)+iy]=pi/6

so now sketch from (-2,0) ray at angle pi/6 (@)

The equation of the line would just be y=arctan(@)x-2

(rt3)y=x-2(rt3)

I know this Q has been answered kinda but would that be right?