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stoichiometry
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hanyi:
calculate the mass of sodium carbonate (Na2CO3.10H2O) required to make 250mL of a 0.100 M solution.
thank you !!!
fun_jirachi:
Using c=n/V, we have that 250mL of a 0.1M solution has 0.0250 moles of Na2CO3. Finding that the molar mass of Na2CO3 is 105.988 g/mol, multiply the two together to get about 2.65g (3SF).
Hope this helps :)
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