bearing help past exam!!!2008

[dreamz]

can someone help me in this bearing and the question 5 of the table

[xXNovaxX]

lol, i skipped that 1st bearing question ROFL

sorry no help =(

[techhatesme]

see attached

sorry for my crappy writing, using the mouse.

By extending the BC line, we find that it is the same bearing as B, 120^o

Then, under the properties of parallel lines, the 60^o, that we find by 180^o - 120^o, is vertically opposite to the angle we want.

Thus, working backwards bearings, 360^o-60^o = 300^o

Hope i have explain it well, if not, let me know.

[TonyHem]

I guess A for Q 5.

[kazoospasm]

I guess A for Q 5.

That's what I got   

Total no. of phones/No. of houses
(0+78+60+36)/154 = 1.1299

[dreamz]

how did you get (0+78+60+36)/154 = 1.1299

[kazoospasm]

The bottom row shows the total number of households that have a given number of mobiles.
34 houses have none => 34*0 = 0
78 have 1 => 1*78 = 78
30 have 2 => 2*30 = 60
12 have 3 => 3*12 = 36