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October 21, 2025, 09:06:31 pm

Author Topic: Vectors  (Read 1926 times)  Share 

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kenhung123

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Re: Kinematics
« Reply #15 on: November 11, 2009, 10:54:07 am »
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Good luck with physics!

GerrySly

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Re: Circular Functions
« Reply #16 on: November 11, 2009, 11:11:27 am »
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VCE 2009
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kenhung123

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Re: Circular Functions
« Reply #17 on: November 11, 2009, 11:28:38 am »
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how do you get that maths notation?

GerrySly

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Re: Circular Functions
« Reply #18 on: November 11, 2009, 11:40:01 am »
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It's just , Wikipedia has a good page on it's syntax. Just use there skeletons and enclose them in tex tags.

Code: [Select]
[tex]\sqrt{2}\cos{(\frac{x}{3})&=-1[/tex]
^^ That is what I wrote for your original equation
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kenhung123

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Re: Vectors
« Reply #19 on: November 11, 2009, 12:24:32 pm »
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Posted new question

THem

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Re: Vectors
« Reply #20 on: November 11, 2009, 01:55:20 pm »
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you don't really anti-differentiate something unless they tell you the situation
is defined by some equation or some vector.

a = -9.8j ( a = dv/dt)
v = -9.8tj + c

You can't really go any further because you don't know the velocity
at any point in time

Sorry I don't really have a better explanation and I have to go to Physics now ;d, good luck with it.


Haha sorry again, I made a mistake here. I just realised in the car.
The ball is going up, not down, dunno what I was thinking xD

So yeah, the ball goes up and you don't know the velocity that it takes. It could be v = 3.32432432 ms^-1 at one point, then be 4.32432432 at another. My point is you can't make or have an equation to anti-differentiate unless you're given one that defines the path or if it's constant.

Hope that makes sense.