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Motion Question

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sxcalexc:
Hey guys after looking at this question my first thoughts were to find the velocity during the 10th second where t=1 but I then realised that it's still accelerating during the second so you can't do v = d/t. I then though about simultaneous equations of motion but I don't think there are enough values. Care to enlighten me? :)

Collin Li:
It's accelerating uniformly, so you use the constant acceleration equations of motion. You know that it accelerates from rest () and that in the 10th second of motion, it moves 28.5 m, this means that:

, where is the displacement from the starting point at any time t.

We can find , with this formula:

, but since :



Therefore:

and

Using the above equation: , therefore:

sxcalexc:
Cheers collin!

Ps. Love the Yoshi

iamdan08:
Rather than start a new thread I'll post my motion question here:

A car travelling with a constant speed of passes a stationary motorcycle policeman. The policeman sets off in pursuit, accelerating to in 10.0s and reaching a constant speed of after a further 5.0s. At what time will the policman catch up with the car?

Thanks!

ed_saifa:
40 seconds?

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