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November 01, 2025, 11:10:20 am
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Author Topic: the rate graph in exam  (Read 3373 times)  Share 

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monokekie

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the rate graph in exam
« on: November 12, 2009, 12:16:25 pm »
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i got the addition of water   ??? wbu?

because conc of product decrease, collision decrease,  back rate decrease.

more product formed, less reactant present, reactant concentration decreases so forward reaction gradually decreases
« Last Edit: November 12, 2009, 12:21:17 pm by monokekie »
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well the limit can turn into a threshold..

Dark Horse

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Re: the rate graph in exam
« Reply #1 on: November 12, 2009, 12:19:54 pm »
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I said removal of product
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methodsboy

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Re: the rate graph in exam
« Reply #2 on: November 12, 2009, 12:21:13 pm »
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kdgamz

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Re: the rate graph in exam
« Reply #3 on: November 12, 2009, 12:24:35 pm »
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vcestudy123

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Re: the rate graph in exam
« Reply #4 on: November 12, 2009, 12:25:50 pm »
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i said dilution
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monokekie

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Re: the rate graph in exam
« Reply #5 on: November 12, 2009, 12:26:50 pm »
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Quote from: vcestudy123 on November 12, 2009, 12:25:50 pm
i said dilution
'

oh yeah~ HIGH FIVE ~ lalah
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well the limit can turn into a threshold..

jbchea

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Re: the rate graph in exam
« Reply #6 on: November 12, 2009, 12:35:21 pm »
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The answer is either the removal of product, or apparently the addition of a base.

I put neither of them, so meh.
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Squida

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Re: the rate graph in exam
« Reply #7 on: November 12, 2009, 12:37:19 pm »
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removal of product omg yay
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TheJosh

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Re: the rate graph in exam
« Reply #8 on: November 12, 2009, 12:39:21 pm »
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buut didnt the back reaction increase???
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Squida

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Re: the rate graph in exam
« Reply #9 on: November 12, 2009, 12:40:23 pm »
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i had no idea what was happening lol
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Dark Horse

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Re: the rate graph in exam
« Reply #10 on: November 12, 2009, 12:41:06 pm »
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If dilution, concnetration of all species decreases, hence, the rate of the forward reaction should also decrease instantaneously, just by a differing amount i think. Back reaction will gradually increase to patrially oppose the change. Anyway, explaining it was the main part, which I screwed up :(
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mystikal

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Re: the rate graph in exam
« Reply #11 on: November 12, 2009, 12:42:56 pm »
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awww dam i said removal of reactant =(
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TheJosh

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Re: the rate graph in exam
« Reply #12 on: November 12, 2009, 12:43:05 pm »
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i think some reactants was removed, then the system opposed by increase in back reaction and decrease in forward reaction?....i dont know...
Quote from: mystikal on November 12, 2009, 12:42:56 pm
awww dam i said removal of reactant =(

same

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rajah21

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Re: the rate graph in exam
« Reply #13 on: November 12, 2009, 12:44:44 pm »
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I said removal of reactant as well, as after the change the rate of the back reaction increased while that of the forward reaction decreased? :S
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hedz

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Re: the rate graph in exam
« Reply #14 on: November 12, 2009, 12:45:44 pm »
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How can it be removal of product, if u remove the product it'll shift forward, and the rate of forward reaction would increase. But it didnt, it decreased.
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