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November 01, 2025, 09:00:23 am

Author Topic: Acceleration  (Read 2550 times)  Share 

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/0

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Re: Acceleration
« Reply #15 on: January 05, 2010, 01:54:05 am »
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No superflya, in uniform circular motion there is always the centripetal force, which is directed towards the centre of the circle. The force changes the 'direction' of the speed, and hence the velocity, but it doesn't actually affect the speed.

It doesn't affect the speed because the centripetal force is at all times perpendicular to the velocity. In a sense, it 'tugs' the velocity vector to change direction, but it doesn't change the size of the vector (which is the speed).

Take special care of the word uniform. Uniform circular motion occurs when the only force is towards the centre of the circle.
If you vertically swing a ball tied to a string , it is not undergoing uniform circular motion because it is being affected by the gravitational field, and thus it does not move at constant speed.


The constancy of speed can be proven using mathematics, but isn't that elementary if you haven't learnt about vectors.

From the unit circle in trigonometry, ,

Therefore, two equations describing the circle are ,

Now, to turn this into a dynamic system, where the object is moving around the circle, we can replace with 't' for time.

,

The period of the motion around the circle in this case will be (the period of sin and cos), but that's not very important.

If we differentiate both with respect to time:





These are the horizontal and vertical velocities of the object. Imagine these as being the magnitudes of vectors, pointing horizontally and vertically respectively.

The resultant sum of these vectors is the velocity,



And the length of the velocity vector is the speed!

.

So the speed of an object moving around a circle is constant. No matter what radius or period we choose, the result still stands.
« Last Edit: January 05, 2010, 02:10:52 am by /0 »

superflya

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Re: Acceleration
« Reply #16 on: January 05, 2010, 02:06:12 am »
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my bad soz I'm a tad drained. thanks for clearing it up /0 (;
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kenhung123

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Re: Acceleration
« Reply #17 on: January 05, 2010, 02:09:11 am »
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newtons first law, object will remain at rest or at constant speed unless an unbalanced force acts on it ie. as there are no unbalanced forces ( net force: 0 N) it continues at constant speed.
Yea but for example and object is at rest, it is then lifted vertically up at 2m/s constant speed. So what makes it move at 2m/s since it was first at rest and the net force is 0?

superflya

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Re: Acceleration
« Reply #18 on: January 05, 2010, 02:09:53 am »
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so basically velocity is changing due to directional changes however the speed is still the same
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Re: Acceleration
« Reply #19 on: January 05, 2010, 02:10:40 am »
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so basically velocity is changing due to directional changes however the speed is still the same

yep

superflya

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Re: Acceleration
« Reply #20 on: January 05, 2010, 02:14:40 am »
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sweet.
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kenhung123

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Re: Acceleration
« Reply #21 on: January 05, 2010, 02:27:33 am »
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Superflya do you know what drives the object from rest to move at constant speed when the net force is zero?

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Re: Acceleration
« Reply #22 on: January 05, 2010, 02:32:19 am »
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There would first have to be a net force to move it, which can then be maintained by a net force of 0, I believe.

superflya

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Re: Acceleration
« Reply #23 on: January 05, 2010, 04:56:53 am »
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not too sure bout ur question however as the velocity is constantly changing, the Mass Is accelerating. Hence according to newtons second law, the mass of the stone must have a force applied to it that is producing the acceleration. this force is the centrepetal force acting towards the centre of the circle. Also note that there is a reaction force associated with the centrepetal force. This reaction force doesn't act on the body moving in a circular path, it acts directly away from the centre of the circle. Hope that helps :)
« Last Edit: January 05, 2010, 05:03:27 am by superflya »
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superflya

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Re: Acceleration
« Reply #24 on: January 05, 2010, 05:06:49 am »
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I believe aqirus' theory sounds pretty reasonable as there has to be an initial force to lift it off the ground to it's desired height then only can the net force = 0.
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