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November 08, 2025, 04:07:44 am
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Author Topic: Volumetric analysis of acids and bases  (Read 814 times)  Share 

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shokstar

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Volumetric analysis of acids and bases
« on: February 07, 2010, 10:11:50 pm »
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What volume of 0.100 M sulfuric acid would be required to neutralise a solution containing 0.500g of sodium hydroxide and 0.800g of potassium hydroxide?

Im very confused. Thanks
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shokstar

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Re: Volumetric analysis of acids and bases
« Reply #1 on: February 07, 2010, 10:14:34 pm »
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Maybe i shouldve searched first the forum first.

Please delete
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herzy

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Re: Volumetric analysis of acids and bases
« Reply #2 on: February 07, 2010, 10:15:56 pm »
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1) find the n(OH-)
0.5/m(NaOH) + 0.8/m(KOH) = n(OH-)
neutralisation is where n(H+) = (OH-) therefore it is the same. n(H2SO4) = 2 x n(H+)

2) n(H2SO4) = 2xn(OH-)
3) volume required is 10 x n(H2SO4) because it is a 0.1 molar solution.

sorry, no calc...
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2009 ENTER = 99.85
2010 - Science/Law at Monash
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