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Exam 1 Graphs & Relations Answers

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hifer:
My answers..
1. D
2. C
3. E
4. B
5. D
6. E
7. C
8. B
9. A

reg:
Graphs and relations Q9.

Objective function: Z = 2x + ky, maximum occurs only at (100, 0).

Hence

200 = 2x + ky
y = (200 - 2x) / k

Function exists at both (100, 0) and (50, 50), this can only be true when k = B = 2 (not k = 1, A).

Unless I'm horribly wrong :(.

SilverBullet:
got 4 or five right which is not a bad result for myself

Odette:

--- Quote from: "reg" ---Graphs and relations Q9.

Objective function: Z = 2x + ky, maximum occurs only at (100, 0).

Hence

200 = 2x + ky
y = (200 - 2x) / k

Function exists at both (100, 0) and (50, 50), this can only be true when k = B = 2 (not k = 1, A).

Unless I'm horribly wrong :(.
--- End quote ---


Lol I got B for Qn 9 as well ... worked it out differently though :P

hifer:

--- Quote from: "reg" ---Graphs and relations Q9.

Objective function: Z = 2x + ky, maximum occurs only at (100, 0).

Hence

200 = 2x + ky
y = (200 - 2x) / k

Function exists at both (100, 0) and (50, 50), this can only be true when k = B = 2 (not k = 1, A).

Unless I'm horribly wrong :(.
--- End quote ---


umm, if K = 2, at  (50,50) Z also = 200

Which means there 2 maximums, which can't be true...

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