Login

Welcome, Guest. Please login or register.

November 01, 2025, 09:09:36 am

Author Topic: Structures question  (Read 663 times)  Share 

0 Members and 2 Guests are viewing this topic.

confusedperson123

  • Victorian
  • Trailblazer
  • *
  • Posts: 36
  • Respect: 0
Structures question
« on: March 20, 2010, 09:33:54 am »
0
(Heinemann 7.8)

A ladder of length 4.8m and mass 16kg is leaning against a wall so that it makes an angle of 65degrees to the horizontal. Calculate the magnitude of the torque exerted on the ladder (taken around where it contacts the ground) by each of the following forces:
1) weight of the ladder

Answer  = F×rsin = 160×2.4×sin25° = 160 N m

why do we use 25 instead of 65?

thanks

superflya

  • Victorian
  • Part of the furniture
  • *****
  • Posts: 1763
  • EL-Heat.
  • Respect: +8
Re: Structures question
« Reply #1 on: March 20, 2010, 10:58:14 pm »
0
because u have to use the angle the ladder makes with wall not the horizontal.to find this angle: 180-65-90=25.
2010- English, Methods (CAS), Physics, Specialist, Chem.
2011- Bachelor of Commerce/Aerospace Engineering - Monash


"The day i stop learning, is the day i walk away from the game" Michael Jordan.

median

  • Victorian
  • Adventurer
  • *
  • Posts: 9
  • Respect: 0
Re: Structures question
« Reply #2 on: May 27, 2010, 07:40:17 pm »
0
u can use cos65 instead.

lachymm

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 379
  • Respect: +1
Re: Structures question
« Reply #3 on: May 28, 2010, 04:38:24 pm »
0
calculates the torque as F * distance = Torque

Therefore the sin(25) part is finding the horizontal distance. Draw a diagram of the ladder leaning on the wall and use SOHCAHTOA and you will realize why you use 25 degrees instead of 65 degrees.
2009 Further Mathematics [41]

Enter 95+