Author Topic: volume of revolution (Read 580 times) Tweet Share

Chavi · « **on:** April 12, 2010, 10:26:54 pm »

Hey, this question is really bugging me, any help would be appreciated.

An area, A, is bounded by the Y-axis, the lines $x = 0.5$ and $y=1.5x$ and the curve with the equation $y = \frac{1}{\sqrt{1 - x^2}}$
Find the solid of revolution formed by rotating the region A about the X-axis. Express in exact form.

Stroodle · « **Reply #1 on:** April 12, 2010, 11:05:01 pm »

To get the volume I think you need to evaluate the integral:

$V=\int_{0}^{\frac{1}{2}}\pi\left( \frac{1}{\sqrt{1-x^2}}\right )^2 -\pi\left (\frac{3}{2}x\right )^2\ dx$

*edit - I learnt this from watching calc lectures, so I'm not 100% sure it's correct. But it makes sense when you think of each 'function' as just being the radius of a circle.

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Author Topic: volume of revolution (Read 580 times) Tweet Share

Chavi

volume of revolution

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