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November 01, 2025, 03:14:11 pm

Author Topic: Gloamy's Thread of Kweshchuns  (Read 7083 times)  Share 

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Re: Gloamy's Thread of Kweshchuns
« Reply #30 on: May 26, 2010, 01:50:59 am »
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lol washers


washers



lol

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Re: Gloamy's Thread of Kweshchuns
« Reply #31 on: May 26, 2010, 09:44:43 pm »
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nope i mean why didnt you use washers? i used washers :S. i thought the "solid" required was that formed outside the cone shape in the middle. the q was ambiguous.

I thought about using washers before I attempted the question because I was looking through the lecture notes, but I couldn't find a way to label the "outer" and "inner" solids.

oooo you do it the intuitive way. *high five* What Gloamy is doing is exactly that. Formally.

Really?

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Re: Gloamy's Thread of Kweshchuns
« Reply #32 on: May 26, 2010, 10:36:14 pm »
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Yeah that's what that calculus stuff is doing. Its basically en masse.
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Re: Gloamy's Thread of Kweshchuns
« Reply #33 on: May 27, 2010, 02:42:40 pm »
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I'm having trouble finishing off this question (even though it's pretty easy for most people):



Using long division, I've managed to simplify it to:



Let


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Re: Gloamy's Thread of Kweshchuns
« Reply #34 on: May 27, 2010, 02:47:47 pm »
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You might have to try partial fractions

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Re: Gloamy's Thread of Kweshchuns
« Reply #35 on: May 27, 2010, 02:54:44 pm »
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You might have to try partial fractions

Oh noes... I'm screwed.

On a side note, is there a way to relate with somehow with common factors?  Or would it be easier/better to use partial fractions like you said?

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Re: Gloamy's Thread of Kweshchuns
« Reply #36 on: May 27, 2010, 06:49:22 pm »
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You might have to try partial fractions

Oh noes... I'm screwed.

On a side note, is there a way to relate with somehow with common factors?  Or would it be easier/better to use partial fractions like you said?

Looks like a partial fraction job to me. Not a very difficult one. Would certainly be way less complex than relating them using common factors (if that can even be done?)
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Re: Gloamy's Thread of Kweshchuns
« Reply #37 on: May 27, 2010, 07:04:40 pm »
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You might have to try partial fractions

Oh noes... I'm screwed.

On a side note, is there a way to relate with somehow with common factors?  Or would it be easier/better to use partial fractions like you said?

Looks like a partial fraction job to me. Not a very difficult one. Would certainly be way less complex than relating them using common factors (if that can even be done?)

That's what I was wondering - whether or not it's possible to use common factors.  I thought I was missing something but I guess partial fractions would be the way to go.

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Re: Gloamy's Thread of Kweshchuns
« Reply #38 on: May 27, 2010, 08:01:06 pm »
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there are no common factors.
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Re: Gloamy's Thread of Kweshchuns
« Reply #39 on: May 28, 2010, 04:31:14 pm »
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I think you should use partial fractions for this. I tried finding factors that are common to the numerator but I don't think it works for this type of question.
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Re: Gloamy's Thread of Kweshchuns
« Reply #40 on: May 30, 2010, 04:43:07 pm »
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With regards to that question, I got the answer, but I just want to check my method to see if it is "mathematically sound" or if it was a fluke.  So the question was:



I simplified it to:



Then as suggested above, using partial fractions:





Sub x=0:



and



Sub x=1:










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Re: Gloamy's Thread of Kweshchuns
« Reply #41 on: May 30, 2010, 06:15:19 pm »
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it was a fluke, when doing the partial fractions you should have instead of

it just turned out that when you subbed numbers in you got the same result :S
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Re: Gloamy's Thread of Kweshchuns
« Reply #42 on: May 30, 2010, 06:16:48 pm »
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The reason the answer was same because the number you subbed in was 1 lol so 1^3 = 1
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Re: Gloamy's Thread of Kweshchuns
« Reply #43 on: May 30, 2010, 10:14:49 pm »
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it was a fluke, when doing the partial fractions you should have instead of

it just turned out that when you subbed numbers in you got the same result :S

Ah, that's where I made the mistake.  Cheers.

The reason the answer was same because the number you subbed in was 1 lol so 1^3 = 1

Then I guess it was truly a fluke because I always sub in 0 and 1 just to make sure.

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