redox in multi - choice

[Martoman]

Ok these are really annoying.

Anyone found a way to do them quickly?

I usually do: oxidation numbers
                 - if its a substitution reaction
                  - if number of C-O bonds increase -> oxidation.

[naved_s9994]

Ok these are really annoying.

Anyone found a way to do them quickly?

I usually do: oxidation numbers
                 - if its a substitution reaction
                  - if number of C-O bonds increase -> oxidation.

Reduction, electrons on the left of arrows,
Oxidation, electrons on the right of arrows.

[Studyinghard]

Ok these are really annoying.

Anyone found a way to do them quickly?

I usually do: oxidation numbers
                 - if its a substitution reaction
                  - if number of C-O bonds increase -> oxidation.

Reduction, electrons on the left of arrows,
Oxidation, electrons on the right of arrows.

but normally they will give you the full balanced equation.

[matty.k]

just unbalance the equation xD

[m@tty]

Ok these are really annoying.

Anyone found a way to do them quickly?

I usually do: oxidation numbers
                 - if its a substitution reaction
                  - if number of C-O bonds increase -> oxidation.

Look if some molecule consisting of only 1 element eg I₂ O₂ N₂ etc. is split and is then bonded to other atoms. This is always a redox reaction. Also look for the addition of oxygen like you said.

It doesn't really take that long anyway, just look for a change in oxidation numbers...

[Stroodle]

Yeah. I find it faster to eliminate ones that aren't redox first, rather than looking for the one that is.