Free Trial Exam Available (solutions released)

[Mao]

Electrical conductivity asked in that manner is fair game. In a nutshell, the more ions you have the more conductive it is. Thus the question is really asking about the degrees of ionisation of acids and bases (i.e. strength of acids and bases)

[happyhappyland]

Electrical conductivity asked in that manner is fair game. In a nutshell, the more ions you have the more conductive it is. Thus the question is really asking about the degrees of ionisation of acids and bases (i.e. strength of acids and bases)

They can assess anything from unit 1 and 2 I guess, but I highly doubt they would waste a question on that. They rather use it for unit 4.

[chansthename]

http://www.vcaa.vic.edu.au/vcaa/vce/exams/examcovers/June_2010_covers/2010chem1-cover.pdf

Sample: Number of questions and marks allocated may vary from the information indicated

[KBT]

Solutions are now out

[m@tty]

http://www.vcaa.vic.edu.au/vcaa/vce/exams/examcovers/June_2010_covers/2010chem1-cover.pdf

Sample: Number of questions and marks allocated may vary from the information indicated

Yeah, that's their way out if they have to change it for whatever reason. HIGHLY unlikely though I'd say.

[andy456]

5. B
Considering that this is a hydrated sample of barium chloride, the remaining percentage by mass
of the compound must be water. Therefore the percentage of water in the compound is:
100 – 52.34 – 27.07 = 20.59
From here, conventional empirical formula calculations can be used.
Species: Ba Cl H2O
Mass: 52.34 27.07 20.59
M: 137.3 35.5 18
Mol: 0.3812090 0.762535 1.14388
Ratio: 1 2 3
Therefore, BaCl2.3H2O

BaCl2.3H2O is option D or am I missing something

[KBT]

5. B
Considering that this is a hydrated sample of barium chloride, the remaining percentage by mass
of the compound must be water. Therefore the percentage of water in the compound is:
100 – 52.34 – 27.07 = 20.59
From here, conventional empirical formula calculations can be used.
Species: Ba Cl H2O
Mass: 52.34 27.07 20.59
M: 137.3 35.5 18
Mol: 0.3812090 0.762535 1.14388
Ratio: 1 2 3
Therefore, BaCl2.3H2O

BaCl2.3H2O is option D or am I missing something

You're correct XD

Hopefully most people find that self-evident on reading the solution

[cameron_15]

Wow, That was very hard! A good challenge though, I got about 80% of it out which I'm happy with.

Also learnt some new things!

Thank you very much

[kakar0t]

Excellent exam, hope VCAA one isn't like this =]

[kyzoo]

Ok just did it.

Cool exam and very nice effort on solutions =)

Its a bit dodgy though in that it's not really clear what some of the short answer explanation question are asking for.

And sif drawing the deoxyribotrinucleotide molecule is 3 marks >.<.

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Also with the solutions for the deoxyribotrinucleotide molecule, aren't the nitrogenous bases meant to be flipped around (horizontally) so that they are "open" to undergo complementary base pairing?

[stonecold]

Yeah, I just gave up on that question.  I drew one of them the right way and all, but then when we had to flip adenine I was like F**k this....it is never going to come up in the exam.

[Martoman]

WTF the data book is so crap for the drawing of nucleotides........................... the pyrimidines you have to rotate so many times.....................

ACTUALLY lol you don't have to rotate them at all >.<

Purines though...................... you need to just flip.

[kyzoo]

Also, the top phosphate group in the same nucleotide as C. It has an OH and O- group, not 2 O- groups.

[appianway]

I really liked the first extended response question. I did feel that question 8 in the multiple choice was beyond the knowledge of the course - I don't know if we're supposed to know when different things decompose. It was definitely more difficult and probing than other trials, so congratulations on the good work Tbh, the first extended response reminded me a bit of the Chemistry NQE... although obviously tailored to fit within the bounds of the VCE course...

How did everyone go on it, btw?

[tcg93]

I think the answers to Q5 & 6 of MC have been flipped