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November 01, 2025, 12:37:04 pm

Author Topic: Reaction Shifting to maintain equilibrium  (Read 2255 times)  Share 

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shinny

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Re: Reaction Shifting to maintain equilibrium
« Reply #15 on: June 20, 2010, 08:18:42 pm »
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Hmm doesn't really make sense how you can alter the yield without altering the rate of a forward/backward reaction. Like if everything proceeds normally, it would have the same yield?

Basically what m@tty said, but yeh, you don't necessarily have to run faster to run further; you can just take a longer time to get there.
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physics

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Re: Reaction Shifting to maintain equilibrium
« Reply #16 on: June 20, 2010, 08:28:06 pm »
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i have an assessment task tomorrrow already D: about fast and slow chemsistryy D:
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kenhung123

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Re: Reaction Shifting to maintain equilibrium
« Reply #17 on: June 20, 2010, 08:54:25 pm »
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Like doesn't Le Chateliers principle describe the establishment of new equilibrium as being one that does not alter the rate of a reaction but the yield of products and reactants? Lets say at equilibrium A+B=>C every second 1 A, B and C is formed. If we don't speed up the formation or A's and B's or C's, then how can we alter the amount of A, B, C. i.e. we are consistent that 1 A, B and C is formed per second.

naved_s9994

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Re: Reaction Shifting to maintain equilibrium
« Reply #18 on: June 20, 2010, 09:47:01 pm »
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LCP is that if a chemical system at equilibrium experiences a change in Concentration, Temp,Vol, or TOTAL pressure, the equilibrium will shift in order to minimize that change.

Hence a system will resist any changes made to its eq by opposing the change.

And yes, hence the relative amounts of reactants and products then may be changed.
« Last Edit: June 20, 2010, 09:49:07 pm by naved_s9994 »
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fady_22

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Re: Reaction Shifting to maintain equilibrium
« Reply #19 on: June 21, 2010, 06:48:26 pm »
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Like doesn't Le Chateliers principle describe the establishment of new equilibrium as being one that does not alter the rate of a reaction but the yield of products and reactants? Lets say at equilibrium A+B=>C every second 1 A, B and C is formed. If we don't speed up the formation or A's and B's or C's, then how can we alter the amount of A, B, C. i.e. we are consistent that 1 A, B and C is formed per second.

If you change the conditions, the system is no longer at equilibrium.
Therefore, the rate can change to ADJUST to the change in conditions, until a new equilibrium is established.
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kenhung123

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Re: Reaction Shifting to maintain equilibrium
« Reply #20 on: June 21, 2010, 07:05:00 pm »
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Sorry I read the text wrong. It said that the overall rate cannot be changed not that the forward and backward rate cannot be changed. Because as conditions change, products may increase to counteract the change. Now as we have more products, more reactants would also be formed as a consequence. So therefore the overall rate is not changed but of course the forward and backward needs to change in order to counteract.