Circle Geometry Help

[wildareal]

Hi Could someone please tell me how you would do Questions 5 and 6 of this paper on the topic of Circle Geometry. Much Appreciated. 

[theuncle]

5a) use <DAC = <DBC
also, <AXP = <QXC
from here it's a matter of adding values to make sure the triangles add to 180
I just let x=<QBX and went from there

5b) just focus on the triangle BXC. using previous answer, we know BQX is an isosceles triangle and therefore XQ = BQ, then prove that <QXC = <QCX by adding angles to 180, this proves that it is also an isosceles triangle with CQ = XQ = BQ

6a) FAC is an equilateral triangle, ie. all angles are 60

6b) FOC is half that triangle, FC by pythag is sqrt(, from before <OCF = 60, use sin(60) = FO/FC

6c) I didn't know this: http://math.about.com/od/formulas/ss/surfaceareavol_2.htm
r=2, s is the hypotenuse of a right angled triangle of sides 1m and 2m ie. sqrt(5)

Hope this helps!