Author Topic: Polar to Cartesian (Read 575 times) Tweet Share

wildareal · « **on:** August 05, 2010, 12:40:44 am »

r=a/(1+Cos(x))

/0 · « **Reply #1 on:** August 05, 2010, 01:33:53 am »

$r = \frac{a}{1+\cos{\theta}}$ .

$\Rightarrow r = \frac{a}{1+\frac{x}{r}}$ (Using $x = r\cos{\theta}$ )

$\Rightarrow a = r+x$

$a -x= \sqrt{x^2+y^2}$ (Using $r = \sqrt{x^2+y^2}$ )

$a^2-2ax+x^2 = x^2+y^2$

$a^2-2ax=y^2$

$x = \frac{1}{2a}(a^2-y^2)$

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Author Topic: Polar to Cartesian (Read 575 times) Tweet Share

wildareal

Polar to Cartesian

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Re: Polar to Cartesian

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