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November 01, 2025, 03:08:13 pm

Author Topic: Newtons law of cooling  (Read 1036 times)  Share 

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lisafaustina

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Newtons law of cooling
« on: September 21, 2010, 11:59:59 am »
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Can somebody plz verify the formula?
Is it k(T-Ts) or -k(T-Ts)
Thanks  :smitten:
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sajib_mostofa

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Re: Newtons law of cooling
« Reply #1 on: September 21, 2010, 12:36:24 pm »
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It's if its cooling down

cameron_15

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Re: Newtons law of cooling
« Reply #2 on: September 21, 2010, 12:38:59 pm »
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k is a constant, it shouldn't matter...

When the object is hotter than the surrounds, it will cool down, k will be negative.

When the object is colder than the surrounds, it will heat up, k will be positive.

either of those will get you the right answer, when you solve for k the calculus will take care of you. Having said that, I'd just run with k(T-Ts) for simplicity.
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sajib_mostofa

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Re: Newtons law of cooling
« Reply #3 on: September 21, 2010, 12:45:27 pm »
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But when you integrate, isn't the sign of k going to influence what expression you get?

Martoman

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Re: Newtons law of cooling
« Reply #4 on: September 21, 2010, 01:07:33 pm »
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Not if you take it out of the integration.
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cameron_15

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Re: Newtons law of cooling
« Reply #5 on: September 21, 2010, 01:10:14 pm »
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Yes, but then when you evaluate k, it will also influence the expression you get.

So if you are using -k(T-Ts) but the object is heating up, the value of k (when evaluated) should be negative. ie -(-K)(T-Ts) = k(T-Ts)



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sajib_mostofa

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Re: Newtons law of cooling
« Reply #6 on: September 21, 2010, 01:12:53 pm »
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Ahh yes I see. Thanks