TSSM 08 Exam 2 - errors? or ..

[vidang]

Networks Q3.
wtf solutions makes no sense whatsoever
my end matrix result looks like:
0 0 0 0
3 1 2 0
1 0 1 0
0 0 0 1

Matrcies Q3d+e
for q3d = i got 13 ill animals
in matrix form (3x1)
i just did T^3 x P0
82.486
12.985
13.74
no clue how they got 11

and q3e = just doesn't make any sense tried on calc nothing really adds up
anyone care to explain

thanks.

[Albeno69]

have you got the 2010 solutions?

[vidang]

yeah i'll uplaod on friday when my cap is restarts

[Albeno69]

yeah i'll uplaod on friday when my cap is restarts

thanks

[_avO]

Networks Q3.
wtf solutions makes no sense whatsoever
my end matrix result looks like:
0 0 0 0
3 1 2 0
1 0 1 0
0 0 0 1

When doing the normal method of a simple row-column reduction we end up finding the 'smallest' ranking. In this case the result would be
A - Feeding/Cleaning
B - Reception
C - Exercising
D - Cleaning/Feeding
This is right if the ranking was 1 = best, 10 = worst


But in this case, 1 = worst, 10 = best
So the manager wants the highest as opposed to the smallest.
So what you do is subtract each rank from the highest possible rank (10). This is called minimisation (but its not always to minimise, such as in this context)

10 10 10 10             6 7 4 3
10 10 10 10             8 7 5 2
10 10 10 10     -       8 8 6 4
10 10 10 10             7 8 5 5

4 3 6 7
2 3 5 8
2 2 4 6
3 2 5 5

From here follow the hungarian algorithm and you'll get the answer

Matrcies Q3d+e
for q3d = i got 13 ill animals
in matrix form (3x1)
i just did T^3 x P0
82.486
12.985
13.74
no clue how they got 11

and q3e = just doesn't make any sense tried on calc nothing really adds up
anyone care to explain

thanks.

Did you double check the numbers?
Try it again
I ended up getting 11.39 which rounds down to 11 ill animals using what you did, P3 = T^3 x P0

[vidang]

holy shit i never spotted out the rank 10 thanks man
and yeah matrix i entered 0.05 instead of 0.005

and how do you do q3e

[_avO]

Steady state matrix = T^50(or some high number) x S0
'two calculations' use another value (80? anything)
T^80 x S0 = ___
Just means in the long term (50 or 80 months) as they are percentages, it will eventually meet an equilibrium.