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November 08, 2025, 05:14:56 am

Author Topic: Interesting practice  (Read 1503 times)  Share 

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Martoman

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Interesting practice
« on: September 27, 2010, 07:36:43 pm »
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For those interested in some exam 1 practice, this was handed to me recently. I thought it pertinent to the course given how easy last years was.

Evaluate:
2009: Math methods: 50, Psychology: 44
2010: chem 47, further 48, Spesh 49 fml seriously and other yr 11 subs.
2011: Holidaying, screw school.
No. Not azn.
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ghadz7

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Re: Interesting practice
« Reply #1 on: September 27, 2010, 07:42:30 pm »
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0.5 ?
[2009]
Methods [46]
[2010]
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[2011]
Architecture

Martoman

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Re: Interesting practice
« Reply #2 on: September 27, 2010, 07:45:08 pm »
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yep :P
2009: Math methods: 50, Psychology: 44
2010: chem 47, further 48, Spesh 49 fml seriously and other yr 11 subs.
2011: Holidaying, screw school.
No. Not azn.
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Swedish meal time all the time

ghadz7

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Re: Interesting practice
« Reply #3 on: September 27, 2010, 07:45:56 pm »
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Sweet, I still remember Methods from last year! :)
[2009]
Methods [46]
[2010]
English; Chemistry; Physics; Further; Specialist; UMEP Maths
[2011]
Architecture

vea

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Re: Interesting practice
« Reply #4 on: September 27, 2010, 07:46:34 pm »
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I worked it out by evaluating 0.5log(_____)^2

Is there a faster way?
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brightsky

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Re: Interesting practice
« Reply #5 on: September 27, 2010, 07:47:13 pm »
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Let

Then







(reject negative solution)

That means,
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the.watchman

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Re: Interesting practice
« Reply #6 on: September 27, 2010, 07:49:48 pm »
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Yep, good :)
Nice exam 1 question!
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Martoman

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Re: Interesting practice
« Reply #7 on: September 27, 2010, 08:01:27 pm »
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yeah brightsky knows what he's doing
2009: Math methods: 50, Psychology: 44
2010: chem 47, further 48, Spesh 49 fml seriously and other yr 11 subs.
2011: Holidaying, screw school.
No. Not azn.
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Swedish meal time all the time

Sunny10

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Re: Interesting practice
« Reply #8 on: September 27, 2010, 11:29:53 pm »
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is it worrying that brightsky's explanation totally lost me?

iNerd

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Re: Interesting practice
« Reply #9 on: September 28, 2010, 09:42:30 am »
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is it worrying that brightsky's explanation totally lost me?
At Y12 yh....? Y11 no? I'm in Y10 doing methods tutoring and I could follow that. Basically he's made the brackets an 'x' and found 'x' in an easier form [ root 10 ] then subbed it back into the expression log10 root10 is now a simple log expression to solve [ MM 1/2 knowledge ].

itolduso

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Re: Interesting practice
« Reply #10 on: September 28, 2010, 10:10:57 am »
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10^x = v(3+v5) + v(3-v5)
(10^x)^2 = (v(3+v5) + v(3-v5))^2
10^(2x) = 10
2x = 1
x = 1/2

naved_s9994

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Re: Interesting practice
« Reply #11 on: September 28, 2010, 10:33:14 am »
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I like that question...It is "interesting" :)
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stonecold

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Re: Interesting practice
« Reply #12 on: September 28, 2010, 10:54:22 am »
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neat question. :)
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8039

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Re: Interesting practice
« Reply #13 on: September 28, 2010, 01:55:23 pm »
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I multiplied log10 by 2 to get log10(10) which would be equal to 1

Then to make it what it were before times both sides by by 1/2 to get log10(sqrt(10)) = 1/2

The only kinda tricky part is realizing all the stuff in the log equals 10 when squared  :-\

« Last Edit: September 28, 2010, 01:59:04 pm by 8039 »

Sunny10

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Re: Interesting practice
« Reply #14 on: September 30, 2010, 12:11:00 am »
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is it worrying that brightsky's explanation totally lost me?
At Y12 yh....? Y11 no? I'm in Y10 doing methods tutoring and I could follow that. Basically he's made the brackets an 'x' and found 'x' in an easier form [ root 10 ] then subbed it back into the expression log10 root10 is now a simple log expression to solve [ MM 1/2 knowledge ].

sigh oh, ive always been a humanities kid, ahh the shame