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November 01, 2025, 03:17:18 pm
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Author Topic: 2008 VCAA Exam 2 - Last question (5f)  (Read 696 times)  Share 

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Ax3

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2008 VCAA Exam 2 - Last question (5f)
« on: October 16, 2010, 08:19:39 pm »
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Hey guys i've had a look at the solutions to this question (i.e showing how to subtract the area of a sector from the full circle or whatever, but i cant figure out how they figured out the angle that subtends from the circle (its 2pi/3).. Can anyone help me out

cheers
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fady_22

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Re: 2008 VCAA Exam 2 - Last question (5f)
« Reply #1 on: October 16, 2010, 08:48:43 pm »
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Draw a triangle.
You have the two radii lengths, of 1, on either side of the angle, and (using the distance formula to find the distance between points (0,0) and (-sqrt(3/2),3/2)) a length of sqrt(3) opposite the angle.
Use the cosine rule to find the angle.
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Ax3

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Re: 2008 VCAA Exam 2 - Last question (5f)
« Reply #2 on: October 16, 2010, 09:10:05 pm »
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ahh cheers thanks alot for that
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