19C - draw yourself a mini-electrochemical series
17D - in electrolysis / electroplating, metal always deposited at negative terminal (which is the cathode in electrolysis) --> hence anode loses mass
15D - delta H for CO2 is not in the data book, and without a delta H value you can only tell that heat will be produced as it is an exothermic combustion reaction - you cannot tell how much heat though, I don't think.
18C - not happy with this question... delta H is negative, so it's definitely exothermic, hence B,D are wrong. As you know from the reaction that for every 2 mol of Al (s), you get 1674 kJ of energy, for 0.5 mol, you should get 1674/4=418.5 mol of heat, which is C, but with a dodgy decimal place. I'm hoping/guessing that that's a typo? I could understand if it were, say, 418.3 mol if they were trying to be smart and take into account (somehow) heat loss / incomplete reaction, but I dunno why it would give off more heat than delta H predicts...
14D - draw a funky little energy profile

5A - more molecules on LHS; exothermic.
6C - you need an acid + a base - C has two bases.