3 Median Line help!!!!!!!!!

[Laith]

question is are there any other methods of finding the 3 median line when no graph is given
some trial papers state use the calculator
how would i do this

[_avO]

If they give you a table of values x and y, then you picture it as a graph and divide it into 3 columns, then do the same method as you would with a graph (i.e. finding the median x and median y values for the lower, middle and upper sections)

[sam.utute]

If they give you a table of values x and y, then you picture it as a graph and divide it into 3 columns, then do the same method as you would with a graph (i.e. finding the median x and median y values for the lower, middle and upper sections)

^ This is the method if you are not using your calculator. If you are, simply input the values and do Med-Med, found just below LinReg.

[onerealsmartass]

If they give you a table of values x and y, then you picture it as a graph and divide it into 3 columns, then do the same method as you would with a graph (i.e. finding the median x and median y values for the lower, middle and upper sections)

^ This is the method if you are not using your calculator. If you are, simply input the values and do Med-Med, found just below LinReg.

yep that is definitely the best way.

[_avO]

Oh so that's what that is for.. Is the b value the same as b = 1/3[(Ylower + Ymid + Yupper) - m(Xlower + Xmid + Xupper)]?

[onerealsmartass]

thats if the b value is the y intercept.

[_avO]

So it might not be the intercept? I don't understand

[TyErd]

y=ax+b, b is always the intercept. so yes the value of b(y-intercept) can be found using that formula.

[onerealsmartass]

_avO are you talking about the equation that comes up on the graph of the CAS?

[_avO]

Oh I was talking about the b value that you get after producing a MedMed line

[onerealsmartass]

yeah so it would come up in the form; y=ax+b im presuming.
so yes the value of b is the intercept and can be found arithmetically using that long formula

[_avO]

Thank god, the CAS has it all I would have used that formula and it would have taken ages

[onerealsmartass]

haha yeah, but sometimes they just provide the graph with no data points so you have to go through the points manually and get the coordinates