URGENT: I need help with some questions!!

[iwannagetA]

The questions are from 2009 exam..

Core.






Geometry and trig










SHOW WORKING OUT!!

[iwannagetA]

Business Related maths

Question 3
Jamie bought a $500 games console on a hire-purchase plan.
He paid $50 deposit and monthly instalments of $25 for two years.
The flat interest rate charged per annum is closest to
A. 15.0%
B. 16.7%
C. 30.0%
D. 33.3%
E. 66.7%


Question 7
A loan of $17 500 is to be paid back over four years at an interest rate of 6.25% per annum on a reducing
monthly balance.
The monthly repayment, correct to the nearest cent, will be
A. $364.58
B. $413.00
C. $802.08
D. $1156.77
E. $5079.29

Question 8
Robin takes out a reducing balance loan of $100 000 with quarterly repayments of $2150.
After seven years of quarterly repayments, Robin still owes $80 000.
Correct to one decimal place, the interest rate per annum for this loan is
A. 6.3%
B. 8.2%
C. 12.9%
D. 18.9%
E. 24.7%

Question 9
To purchase a house Sam has borrowed $250 000 at an interest rate of 4.45% per annum, fixed for ten years.
Interest is calculated monthly on the reducing balance of the loan. Monthly repayments are set at $1382.50.
After 10 years, Sam renegotiates the conditions for the balance of his loan. The new interest rate will be 4.25%
per annum. He will pay $1750 per month.
The total time it will take him to pay out the loan fully is closest to
A. 17 years.
B. 20 years.
C. 21 years.
D. 22 years.
E. 23 years.

[onerealsmartass]

this is for 09 trig Q9
http://vcenotes.com/forum/index.php/topic,31689.0.html
im doing 09 exam now...

[_avO]

Q12 Core, answer C, refer to circle of transformations and read it carefully, internet usage = x

Q13 Core, answer D, find the median x/y for the first 3 points as well as the last three, and do a simple m(x-x1) = y-y1

[iwannagetA]

if got ur answers worked out photocopy them and post them here

[_avO]

I did them in my head o.0

for the first one refer to

Q12 - No if you read it, it says mathematics against internet usage. This represents y vs x
The transformations possible for this graph are:

y^2 vs x
y vs log(x)
y vs 1/x

Now if you refer back to the possible answers, only C (mathematics against log(internet usage)) applies so therefore thats the only answer, no calculations necessary

Q13 - 2nd answer, split into 3 columns, and instead of years put it as 1989 = 1, 1990 = 2 and so forth. Determine the medians for x and y being (2, 0.6) and (8, 3,3). Next do rise over run (3.3 - 0.6) / (8 - 2) = 2.7/6 = 0.45 = 45%

[jasoN-]

1. definitely C (go to page 190 of essentials, or 'The circle of transformations' for any other book), the only viable options are y^2, log(x) or 1/x, you're only given log(x) ie. log(Internet use)

2. Find the median of the first 3 and last 3 points. Coordinates are (1990, 0.6) and (1996, 3.3)
use m = (y2-y1)/(x2-x1) (FYI. you do not need to 'move the line' 1/3 toward the median of the middle. THE GRADIENT IS ALWAYS THE SAME!)
m=(3.3-0.6)/(1996-1990) = 0.45, hence D

geo+trig (don't blame me if my methods are different to convention!)
1. no idea, don't do the module
2. V = bh/2 x l = 160
   V(second prism) = 2b x h / 2 x 3l =3lbh
as lbh/2 = 160, lbh = 320, hence 3lbh = 960, hence C

3. Angle of depression = Angle of elevation(RDA)
Angle(RDA) = tan^-1 (1.5/3. = 21.54 degrees => hence A

4. Need to find magnitude RC
by pythag:
RC =
, A

5. Volume of water is essentially the volume of the 'inner' cylinder
ie. diameter is 29-2x2 = 25mm = 2.5cm
radius = 1.25cm
V=pi x r^2 x length
 = pi x 1.25^2 x 8500cm
 = 41724cm^3 = 42litres (as 1000cm^3 = 1L), hence B

6. The pole falls down and hits the wall; visualise this
The pole is essentially the hypotenuse now, continue from here (probs need some info from the module, idk)

[iwannagetA]

Angle of depression = Angle of elevation(RDA)
Angle(RDA) = tan^-1 (1.5/3. = i got 0.375961 where did u get ur answerrr from

[iwannagetA]

now i need help with the business question

thanksss avo and jason ur really helped.

[iwannagetA]

??/

[shokstar]

Business Math:

q.3
flat rate interest= (100XI)/(PXt)

First, take the deposit away from the purchase price, thats 500-50=$450

Then find out how much he pays in the monthly payments, thats 25X12X2=$600.
 Then the interest paid is how much he paid, minus the purchase price after the deposit has been taken off, so I=600-450=$150.

P in the equation = purchase price after the deposit deducted, and t=2 years, so
r=(100X150)/(450X2)=16.67%, B

q.7
In TVM solver,

N= 48
I= 6.25
PV= 17500
Pmt=?
FV=0
Ppy=12
Cpy=12
End

That means pmt= -413, so the payment is $413.00, B

q.8
TVM solver again,
N= 4X7=28
I=?
PV= 100 000
Pmt = -2150
FV = -80 000
Ppy= 4
Cpy=4
End

I=6.3, A

q.9
TVM again, you have to find FV after 10 years:
N=120, I=4.45, PV= 250 000, Pmt= -1382.50, FV=?, Ppy=12, Cpy=12, End
FV = - 181324

Then use TVM again, this time:
N=?, I=4.25, PV=181324, Pmt = -1750, FV = 0, Ppy=12, Cpy=12, End
N= 129 repayments, 129/12= 10.75 years.

Then add the original 10 years to 10.75 years, you'll get 20.75 which is closest to 21, so C

[iwannagetA]

thanks matee