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November 01, 2025, 10:44:53 am
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Author Topic: VCAA 2008 Exam 2  (Read 714 times)  Share 

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iwannagetA

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VCAA 2008 Exam 2
« on: November 02, 2010, 08:40:47 pm »
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CORE question 4 c)
whats the slope?

part b answer was :  Arm span=-15.63+1.09xHeight
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_avO

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Re: VCAA 2008 Exam 2
« Reply #1 on: November 02, 2010, 08:41:55 pm »
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slope is the gradient (i.e. the coefficient in front of the independent variable) being 1.09
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iwannagetA

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Re: VCAA 2008 Exam 2
« Reply #2 on: November 02, 2010, 08:43:16 pm »
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slope = gradient
ty mate :D
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iwannagetA

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Re: VCAA 2008 Exam 2
« Reply #3 on: November 02, 2010, 08:49:13 pm »
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now Q5a + b

i dont get it?????
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_avO

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Re: VCAA 2008 Exam 2
« Reply #4 on: November 02, 2010, 08:51:59 pm »
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They are asking you to linearise the data using y vs 1/x then finding that r value

then the 2nd bit is just subbing in a value in the equation that you find
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iwannagetA

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Re: VCAA 2008 Exam 2
« Reply #5 on: November 02, 2010, 09:07:37 pm »
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Geometry
Q1 a) we use v=1/2bh?

someone work it out plz
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jasoN-

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Re: VCAA 2008 Exam 2
« Reply #6 on: November 02, 2010, 09:12:14 pm »
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No, you use L*W*H (ie. Area of base x h)
so V = 6*10*.2 = 12
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iwannagetA

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Re: VCAA 2008 Exam 2
« Reply #7 on: November 02, 2010, 09:17:17 pm »
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ok what about b which one do we use for i and ii
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