Diff Question

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andy456

Victorian
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Diff Question

« on: November 04, 2010, 10:38:09 am »

0

Just wanna check what I got because I dont have answers and my calc is dead.

Find d $y= (x^2 - 2x)e^x$ /dx

I got $e^x(x^2-2)$

Hence find antiderivative of $x^2e^x$

Is it $(x^2-2x)e^x + \int2e^x dx$
Thanks

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VCE 2010: Eng 42 | Legal 49 | Chem 37 | MM 34 | Indo SL 33 |
ATAR: 97.45

2011: Bachelor of Arts Monash University
2012: Bachelor of Commerce?? Please!!

costa94

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Re: Diff Question

« Reply #1 on: November 04, 2010, 10:41:23 am »

0

you get integral of x^2 * e^x - 2x * e^x = integral x^2 * e^x - integral 2x * e^x = (x^2 - 2x)*e^x
so re arrange it

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TrueTears

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Re: Diff Question

« Reply #2 on: November 04, 2010, 10:16:59 pm »

0

Quote from: andy456 on November 04, 2010, 10:38:09 am

Just wanna check what I got because I dont have answers and my calc is dead.

Find d $y= (x^2 - 2x)e^x$ /dx

I got $e^x(x^2-2)$

Hence find antiderivative of $x^2e^x$

Is it $(x^2-2x)e^x + \int2e^x dx$
Thanks

yes it's correct

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