CSE 2008

[Studyinghard]

PCl5 ----> PCl3 + Cl2

0.8 mol is initially placed in 4L vessel at 400 degrees and allowed to come to equilibrium. At eq., 0.760 mol of chlorine forms. The constant is..

a) 3.61
b) 7.22
c) 14.4
d) 27.7

ty

[Xavier1234]

PCl5 ----> PCl3 + Cl2

0.8 mol is initially placed in 4L vessel at 400 degrees and allowed to come to equilibrium. At eq., 0.760 mol of chlorine forms. The constant is..

a) 3.61
b) 7.22
c) 14.4
d) 27.7

ty

A. 3.61M

[Studyinghard]

calculations ?

[Xavier1234]

Initial of PCL₅ is 0.8mol.

the ratio is 1:1:1.

and the change in mol of Cl₂ is 0.76mol. that corresponds to 0.76 mol change for both PCl₅ and PCl₃ as well as per the equal ratio.

then subtract 0.8 by 0.76 = 0.04 mol at equilibrium for PCl₅.

then divide the 0.04 by 4L as per the volume and the 0.76 by 4L as well.
then you get the concentration, and then just do the K expression, and voila 3.41