Author Topic: Differential Calculuss =/ (Read 2854 times) Tweet Share

Piney.z · « **Reply #15 on:** May 15, 2008, 10:54:30 pm »

mmm thought so.
so the book is wrong! =/
ty maoo [you go to my friend's school! lol *randomness*]

Mao · « **Reply #16 on:** May 15, 2008, 11:10:35 pm »

Quote from: Piney.z on May 15, 2008, 10:54:30 pm

mmm thought so.
so the book is wrong! =/
ty maoo [you go to my friend's school! lol *randomness*]

am I thinking Phi?

Piney.z · « **Reply #17 on:** May 16, 2008, 12:25:02 am »

oh i've heard of him.. but no
Lol
Harris. some Asian NOOB?

Piney: Hey harris! u knw some kid name Mao in ur school?
harris: Oh yeH! that reallly smart azn kiD?
Piney: YEP!

haha....

dcc · « **Reply #18 on:** May 16, 2008, 07:51:29 am »

Quote from: Mao on May 15, 2008, 10:39:20 pm

$\frac{d}{dx} \cos^{-1}\sqrt{x} = \frac{1}{2\sqrt{x(1-x)}}$

$\implies \int \frac{1}{2\sqrt{x(1-x)}} dx = \cos^{-1}\sqrt{x} +c$

$\implies \frac{1}{2} \int \frac{1}{\sqrt{x(1-x)}} dx = \cos^{-1}\sqrt{x} +c$

$\implies \int \frac{1}{\sqrt{x(1-x)}} dx = 2\cos^{-1}\sqrt{x} +c$

$\frac{d}{dx} \cos^{-1}\sqrt{x} \neq \frac{1}{2\sqrt{x(1-x)}}$

Mao · « **Reply #19 on:** May 16, 2008, 09:26:12 am »

ooops, forgot the negative sign...
[original solution fixed]

[and yes, Harris, lol]

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