how to find direction of induced current

[Chavi]

So the loop has increasing fux from right to left to oppose this a current flows in the thing( ) connected to the ammeter to produce a magneic flux from left to right?

Slightly muddled;
The loops has an induced current from Y-X due to the momentary change in flux in the left solenoid.

Do i have to state the direction of the flux?
Sorry for interupting ure thread TYRED.

Ye. But you shouldn't misquote Lenz.. . .

[TyErd]

so the induced magnetic field will be to the right? and then using grip rule find the direction of current? also I don't get how there is flux in the first place in something like this.

For the left solenoid, use the right hand grip rule - align your thumb in the direction of the current, and then grip it like a banana - the direction that your fingers twirl is the direction of the field lines inside and around the solenoid. Now repeat with but use the opposing field for the right solenoid.

woah! that's awesome, does that work all the time?

[Chavi]

so the induced magnetic field will be to the right? and then using grip rule find the direction of current? also I don't get how there is flux in the first place in something like this.

For the left solenoid, use the right hand grip rule - align your thumb in the direction of the current, and then grip it like a banana - the direction that your fingers twirl is the direction of the field lines inside and around the solenoid. Now repeat with but use the opposing field for the right solenoid.

woah! that's awesome, does that work all the time?

theoretically yes. For VCAA yes. . .

[TyErd]

So the loop has increasing fux from right to left to oppose this a current flows in the thing( ) connected to the ammeter to produce a magneic flux from left to right?

Slightly muddled;
The loops has an induced current from Y-X due to the momentary change in flux in the left solenoid.

Do i have to state the direction of the flux?
Sorry for interupting ure thread TYRED.

all good man,, even I went off topic for a couple of posts.

[Elnino_Gerrard]

For the left solenoid, use the right hand grip rule, and you'll find that the field (flux) moves inside the coil from right to left - meaning that the left side is a North pole.
For the right solenoid, you have an induced field that is opposite to the field generated in the left solenoid. So the Field inside the right solenoid moves from Right to left - making the Right side of the right solenoid a North pole.

That would be enough? without writing the right hand grip rule bit.

[TyErd]

So Chavi, that means there's to ways of solving this problem, your 1st method where you align your thumb in the direction of the current and so forth and also using north and south poles to find the direction of the current and then induced?

[chap]

Am I right in saying the field lines around both coils should look the same?

[Elnino_Gerrard]

So Chavi, that means there's to ways of solving this problem, your 1st method where you align your thumb in the direction of the current and so forth and also using north and south poles to find the direction of the current and then induced?

Pretty sure there both the same thing.

[Chavi]

So Chavi, that means there's to ways of solving this problem, your 1st method where you align your thumb in the direction of the current and so forth and also using north and south poles to find the direction of the current and then induced?

It's the same thing.