Login

Welcome, Guest. Please login or register.

November 01, 2025, 11:01:48 am

Author Topic: Ph when OH- conc is known  (Read 526 times)  Share 

0 Members and 1 Guest are viewing this topic.

Elnino_Gerrard

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 353
  • Respect: +6
Ph when OH- conc is known
« on: November 10, 2010, 10:45:38 pm »
0
At 25 degrees celsius the product =10^-14??? what about other scenarios?
2010 VCE ATAR : 98.35

Xavier1234

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 243
  • Respect: +1
  • School Grad Year: 2010
Re: Ph when OH- conc is known
« Reply #1 on: November 10, 2010, 10:48:12 pm »
0
quantitatively, we wont be asked for higher or lower than 25degrees C. but the effects of it qualitatively yes its examinable.
UniMelb 2011-2013 
Bachelor of Arts (Economics and Geography)


VCE 2010 - 97.35
English[46], Economics[44], Physics[41], Chemistry[38], Further Maths[38]

SixWinged

  • Victorian
  • Trendsetter
  • **
  • Posts: 105
  • Respect: +1
Re: Ph when OH- conc is known
« Reply #2 on: November 10, 2010, 10:51:32 pm »
0
[H+][OH-] = 10^-14

Solve for [H+] and solve as you usually would for pH questions.

EDIT: Sorry misread your post, no we don't need to know how to solve at higher/lower temperatures. Though I would imagine it's technically examinable, but they would "step you through it" so to speak, and provide you with the Kw value.
Specialist [41], Methods [42], English [44], Chemistry [45], Physics [46], IT Applications [47], Further [48]
2010 ATAR: 99.45, congrats to the VCENotes class of 2010 :)
2011: Commerce/Engineering@Monash. Keen to tutor VCE students next year in any of the above subjects except English and IT, feel free to shoot me a PM if you have any questions relating to those subjects, probably won't be on this site often now, but PMs go to my email.

Elnino_Gerrard

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 353
  • Respect: +6
Re: Ph when OH- conc is known
« Reply #3 on: November 10, 2010, 10:52:30 pm »
0
Cool thanks.  :)
2010 VCE ATAR : 98.35