Author Topic: Solving in Polar Form (Read 875 times) Tweet Share

wildareal · « **on:** November 28, 2010, 04:03:27 pm »

Find the solutions of the equation z^4-2z^2+4=0 in polar form.

wildareal · « **Reply #1 on:** November 28, 2010, 04:30:59 pm »

Let m=z^2, complete the square.

You'll get z^2=1+root(3)i

therefore z=root(2)cis(TT/6+TTk)

taiga · « **Reply #2 on:** November 28, 2010, 04:57:41 pm »

are you talking to yourself?

ninbam1k · « **Reply #3 on:** November 28, 2010, 06:07:44 pm »

LOL ^

iNerd · « **Reply #4 on:** November 28, 2010, 06:09:39 pm »

He does this all the time...solves his own questions

wildareal · « **Reply #5 on:** November 28, 2010, 07:23:10 pm »

LOL why is it that people only reply after I've answered it!

Souljette_93 · « **Reply #6 on:** November 28, 2010, 10:22:44 pm »

are you talking to yourself?

:2funny:

You just made my day.

PS: sorry OP, no offence intended.

pi · « **Reply #7 on:** November 28, 2010, 10:27:59 pm »

Let m=z^2, complete the square.

You'll get z^2=1+root(3)i

therefore z=root(2)cis(TT/6+TTk)

just remember there are only going to be 4 solutions... (caution with the TTk part)

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