Author Topic: Complex Number Question (Read 733 times) Tweet Share

wildareal · « **on:** November 29, 2010, 01:00:37 pm »

Given that z=x+iy find z=conjugate(z)

iNerd · « **Reply #1 on:** November 29, 2010, 01:08:03 pm »

Are you going to solve your own question again?

[Sorry, I couldn't resist

]

pi · « **Reply #2 on:** November 29, 2010, 01:12:28 pm »

Given that z=x+iy find z=conjugate(z)

Conjugate... If I remember, the answer should be x-iy

/0 · « **Reply #3 on:** November 29, 2010, 01:13:37 pm »

$x+iy=x-iy$
$\Rightarrow iy=-iy$
$\Rightarrow y=-y$
$\Rightarrow y = 0$

i.e. $z=x$ . z is real, assuming x is real

pi · « **Reply #4 on:** November 29, 2010, 01:16:00 pm »

$x+iy=x-iy$
$\Rightarrow iy=-iy$
$\Rightarrow y=-y$
$\Rightarrow y = 0$

i.e. $z=x$ . z is real.

Oh, he was asking for an equation. Lol, what a strange question...

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