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November 01, 2025, 08:56:39 am

Author Topic: Motion qn help  (Read 771 times)  Share 

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ttn

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Motion qn help
« on: February 08, 2011, 12:33:01 am »
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Is there a quick and easy way to solve these types of problems? The way I did it was a bit too long and complicated.

A motorist is travelling at a constant speed of 120km/h along a freeway when he passes a stationary police car. The police car immediately gives chase, accelerating at 2.4m/s^2 to a speed of 48m/s.

Find the time taken for the police car to catch the motorist.
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xZero

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Re: Motion qn help
« Reply #1 on: February 08, 2011, 12:35:59 am »
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Draw a graph (v to t) for the motorist and the police car. Then equate the area below the graphs to find the time
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ttn

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Re: Motion qn help
« Reply #2 on: February 08, 2011, 12:39:26 am »
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I've got the graph drawn, but how do I go about equaling the area?
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xZero

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Re: Motion qn help
« Reply #3 on: February 08, 2011, 12:43:51 am »
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firstly, let t = time taken for the police car to catch up
so the area under the police car graph should be a trapezium and the motorist should be a square
the area of the motorist should be 120/3.6 x t(remember to convert it to m/s)
the area of the police car should be 0.5 x 48 x ( (t-20) + t)

rest should be simple

Edit: opps haha hate these small mistakes
« Last Edit: February 08, 2011, 01:05:25 am by xZero »
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ttn

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Re: Motion qn help
« Reply #4 on: February 08, 2011, 12:57:28 am »
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I equaled them and it's not getting the right answer?
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ttn

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Re: Motion qn help
« Reply #5 on: February 08, 2011, 01:01:50 am »
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Oh nvm, typed it wrong in calc, but your police car formula is wrong, it should be  0.5 x 48 x ( (t-20) + t), plus not multiply.

Thanks for the help.
2010: IT: Applications [43]
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