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November 01, 2025, 04:20:35 pm
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Author Topic: Madoscar's Question  (Read 3812 times)  Share 

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madoscar65

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Madoscar's Question
« on: February 12, 2011, 11:58:24 pm »
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Hi People,
I can't seem to really interpret this application question, so hope you guys can help

A biathlon event involves running and cycling. kim can cycle 30km/h faster than she can run. if kim spends 48 minutes running and a third as much time again cycling in and event that covers a total distance of 60 km, how fast can she run?

Thanks
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samiira

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Re: Madoscar's Question
« Reply #1 on: February 13, 2011, 12:05:39 am »
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Let the running speed be y km / h

Cycling speed = (y + 30)km / h

Distance covered by running will be  (48/60) X y = 0.8y

Distance covered by cycling = 64/60 X (30 + y) = 32 + 1.067y

0.8y + 1.067y+ 32 = 60

1.867y = 28

y = 28 / 1.867 = 15 km/ h
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madoscar65

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Re: Madoscar's Question
« Reply #2 on: February 13, 2011, 12:17:02 am »
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Omg Thinking about it... It wasn't hard... Doing questions at night just doesen't work for me..
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