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Verbal Reasoning
che0106:
--- Quote from: xD_aQt on February 19, 2011, 09:12:18 pm ---Its from the practice tests for selective entry high school :|
--- End quote ---
which high school?
nacho:
The closest answer is B:
Some Hiffs are Ziffs, but the actual answer should be that ALL Hiffs are Ziffs.
Defs not A
Edit:
Nvm, I read the post below, think i overlooked E D:
funkyducky:
The answer is E -
If all PIFS are ZIFS, then you can consider PIF as being a subset of ZIF, as in, if you had a PIF, it would definitely be a ZIF, but the ZIF would not necessarily be a PIF, because the statements given to us are not commutative, ie. "All PIFS are ZIFS" does not imply that all ZIFS are PIFS. Hence, we can state with certainty that some ZIFS are PIFS ie. E is correct.
simplyme:
I am pretty sure the answer, A, is incorrect, and A B C D E are all incorrect.
simplyme:
My German cousin was trying to help (FYI he's a mathematician :buck2: :buck2:)....There is something confusing to me, if you can make sense out of it..ENJOY LOL
About this Question 20:
All HIFS are PIFS: becomes in short form H>>a>>P
Some SIFS are RIFS: becomes in short form S>>e>>R
All ZIFS are SIFS: becomes in short form Z>>a>>S
All PIFS are ZIFS: becomes in short form P>>e>>Z.
Now i start with H>>a>>P and search for other connections that either star with P or ends with H and connect them with each other: H>>a>>P>>a>>Z>>a>>S>>e>>R
in this case they are all connected to a straight line.
But it could also be possible, that we have for example P>>a>>Z , P>>e>>S , P>>a>>R, P>>e>>H
in this case you would draw four arrows from P to the other sets.
Which of the following do we know is correct.
All ZIFS are RIFS? Z>>a>>R? We know: Z>>a>>S>>e>>R, so there could be one ZIF that is also a SIF but this ZIF might not be a RIF as we only know that there exist some (but not all) SIFS that are also RIFS.
The "rules of connections" state that from Z>>a>>S>>e>>R follows Z>>e>>R. We can not follow that Z>>a>>R.
Some HIFS are ZIFS? H>>e>>Z? From H>>a>>P>>a>>Z follows H>>a>>Z and H>>e>>Z.
So this is true.
In some sense >>e>> is weaker than >>a>>:
If we have a very long chain of for example 200 elements
M1>>a>>M2>>a>>M3....>>a>>M200
gives always a connection M1>>a>>M200 and also M1>>e>>M200.
But if only one connection of the chain is >>e>> then the whole >>a>>..>>a>>.. chain is destroyed by this >>e>> and we only get M1>>e>>M2.
All RIFS are SIFS?: R>>a>>S? We see that R is the last element of this chain. So this is not true.
All HIFS are RIFS? H>>a>>R? H>>a>>P>>a>>Z>>a>>S>>e>>R we see the >>a>> chain is broken by S>>e>>R so this is not true.
Some ZIFS are PIFS? Z>>a>>P? We see P>>a>>Z so we can change the orientation by exchanging a by e:
P<<e<<Z so this is true.
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