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November 01, 2025, 07:58:05 pm
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Author Topic: cot(x) graph?  (Read 1568 times)  Share 

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pi

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cot(x) graph?
« on: February 26, 2011, 12:47:05 pm »
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Does the graph of exist at ?

Because and is undefined. I'm just not sure if the graph will be defined at that point...  Especially as , and using that definition when , . Which definition do I use here?

Thanks
« Last Edit: February 26, 2011, 12:50:11 pm by Rohitpi »
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luken93

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Re: cot(x) graph?
« Reply #1 on: February 26, 2011, 01:00:40 pm »
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Hmmm, that is interesting....

What happens when you graph it and/or 1/undef?
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pi

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Re: cot(x) graph?
« Reply #2 on: February 26, 2011, 01:04:27 pm »
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Quote from: luken93 on February 26, 2011, 01:00:40 pm
Hmmm, that is interesting....

What happens when you graph it and/or 1/undef?

I'm not sure what is... So far I have just been putting an open circle on my basic graph wherever .

These definitions of cotangent seem contradictory here  :o
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jane1234

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Re: cot(x) graph?
« Reply #3 on: February 26, 2011, 06:10:10 pm »
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i think you use cot(x)=cos(x)/sin(x) ... as undefined = k/0, then 1/undefined (the reciprocal) would be 0/k=0. so i would include cot(pi/2)=0 on the graph... my teacher and textbook both didn't omit it...
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luken93

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Re: cot(x) graph?
« Reply #4 on: February 26, 2011, 06:49:21 pm »
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Quote from: jane1234 on February 26, 2011, 06:10:10 pm
i think you use cot(x)=cos(x)/sin(x) ... as undefined = k/0, then 1/undefined (the reciprocal) would be 0/k=0. so i would include cot(pi/2)=0 on the graph... my teacher and textbook both didn't omit it...
Aaah of course....





Tan is undefined when cos(x) = 0





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thushan

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Re: cot(x) graph?
« Reply #5 on: February 26, 2011, 06:53:03 pm »
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cot(x) = 1/tan(x) does not apply when tan(x) = 0.

The raw definition of cot is adjacent/opposite.
cot(x) = 1/tan(x) is not the definition; it is merely an extension of it. It doesn't apply when tan(x) = 0.
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pi

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Re: cot(x) graph?
« Reply #6 on: February 26, 2011, 09:17:56 pm »
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Ok, thanks guys! Got it now.
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