Physics - Motion (3/4)

[bhavsar]

Hey guys got an outcome tomorrow for motion...
Just reading over projectile motion and I just dont seem to get it, I dont understand when to use vertical and when to use horizontal, but vertical in general, am finding hard.
Any tips or explanations??
thanks in advance

[davidle_10]

Time to reach maximum height: vertical t=(v-u)/a   u=initial vertical velocity
Maximum height: vertical x=(v^2-u^2)/2a     u=initial vertical velocity
Total flying time: Time to reach max height X 2 (This is only used for projectiles on a level plane)
Distance traveled: horizontal  D=S/T t=total time the projectile is in the air s=horizontal velocity
Finding the velocity at any point: Use both vertical and horizontal using Pythagoras. V=root(vx^2+vy^2)

If you need further explanations feel free to ask.

[bhavsar]

thats actually quite easy to understand, thanks

[Halil]

Just be careful with the type of questions that are not symmetric. The ones where an object is thrown upwards from a specific height and in which the ball travels up and down falls down.
Do not use the Total flying formula for that question. Instead use the time to get to max height formula, and then use h=ut+0.5gt^2 to find the time to reach the floor after it reaches maximum height.
Also, do not forget that no matter in what path an object travels or how heavy it is, it will drop to the floor at the same time as an object that would fall vertically down.

If you need any type of help pm me and I will try my best to do whatever I can buddy

[bhavsar]

thanks Halil