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November 08, 2025, 02:14:46 pm
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Author Topic: Camo'd question thread ;D  (Read 1396 times)  Share 

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Camo

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Camo'd question thread ;D
« on: March 20, 2011, 07:36:21 pm »
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 :)

So a few questions.

will the following touch the x-axis?
a)f(X)=x^2-5x+2
b)f(X)=3x^2+2x+5

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Water

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Re: Camo'd question thread ;D
« Reply #1 on: March 20, 2011, 07:39:35 pm »
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a)f(X)=x^2-5x+2
b)f(X)=3x^2+2x+5

Find the determinant of each quadratics. If it has one solution, it is touching the x axis.



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pi

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Re: Camo'd question thread ;D
« Reply #2 on: March 20, 2011, 07:41:32 pm »
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+1 to Water's help, except its actually 'discriminant' :)  (as ClimbTooHigh pointed out)


« Last Edit: March 20, 2011, 07:50:02 pm by Rohitpi »
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BubbleWrapMan

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Re: Camo'd question thread ;D
« Reply #3 on: March 20, 2011, 07:47:56 pm »
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Discriminant.
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pi

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Re: Camo'd question thread ;D
« Reply #4 on: March 20, 2011, 07:49:30 pm »
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Quote from: ClimbTooHigh on March 20, 2011, 07:47:56 pm
Discriminant.

True, DAMN THOSE MATRICES!
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Camo

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Re: Camo'd question thread ;D
« Reply #5 on: March 20, 2011, 07:55:12 pm »
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sketch f(X)=2(x+1)^2 this will have intercepts at (-1,0) and (0,5)?
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Camo

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Re: Camo'd question thread ;D
« Reply #6 on: March 20, 2011, 07:55:47 pm »
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sorry (0,4).
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pi

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Re: Camo'd question thread ;D
« Reply #7 on: March 20, 2011, 07:56:47 pm »
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Quote from: Camo on March 20, 2011, 07:55:12 pm
sketch f(X)=2(x+1)^2 this will have intercepts at (-1,0) and (0,5)?

(-1,0) and (0,2)

y-int when x=0
f(0)= 2(1)^2 = 2
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Camo

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Re: Camo'd question thread ;D
« Reply #8 on: March 20, 2011, 07:59:30 pm »
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Rohitpi yours answers are correct for f(x)=2(x-1)^2 i missed up.
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Greatness

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Re: Camo'd question thread ;D
« Reply #9 on: March 20, 2011, 08:12:22 pm »
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f(x)=2(x-1)^2
X ints: (y=0) 2(x-1)^2=0 -> x-1=0 -> x=1 (1,0)(so it touches the x axis)
Y int: (x=0) f(0)=2(0-1)^2 -> y=2 (0,2)
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Camo

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Re: Camo'd question thread ;D
« Reply #10 on: March 20, 2011, 08:15:26 pm »
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express f(X)=x^2+3x-2 and f(X)=4x^2+8x-7 in the form y=a(x+h)^2 and hence the max or min and the range in each.
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Re: Camo'd question thread ;D
« Reply #11 on: March 20, 2011, 08:20:34 pm »
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complete the square:

ill do for 4x^2 + 8x - 7:
y=4(x^2+2x-7/4)
y=4(x^2+2x+1^2-1^2-7/4)
y=4[(x+1)^2-1-7/4]
y=4[(x+1)^2-11/4]
y=4(x+1)^2-11
a is positive, so its a minimum (-1,-11)
range = (-11,infinity)
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Re: Camo'd question thread ;D
« Reply #12 on: March 20, 2011, 10:11:59 pm »
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how would you find x-intercept of -2log e(x+2) ?
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brightsky

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Re: Camo'd question thread ;D
« Reply #13 on: March 20, 2011, 10:12:58 pm »
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Let y = -2loge(x+2)
For x-intercept, let y = 0
-2loge(x+2) = 0
loge(x+2) = 0
x+2 = e^0 = 1
x = -1
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Camo

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Re: Camo'd question thread ;D
« Reply #14 on: March 21, 2011, 11:29:41 am »
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the graph of y=a(x+h)^3+k has a point of zero gradient at (0,4) and passes through (1,1) find the values of a,h and k.
i know k = 4 due to the y-intercept of the zero gradient and its cubic.
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‎"We divert our attention from disease and death as much as we can; and the slaughter-houses and indecencies without end on which our life is founded are huddled out of sight and never mentioned, so that the world we recognize officially in literature and in society is a poetic fiction far handsomer and cleaner and better than the world that really is."
- William James.
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